Optimal. Leaf size=61 \[ \frac{a^3 x^{m+1}}{m+1}+\frac{3 a^2 b x^{m+4}}{m+4}+\frac{3 a b^2 x^{m+7}}{m+7}+\frac{b^3 x^{m+10}}{m+10} \]
[Out]
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Rubi [A] time = 0.0586542, antiderivative size = 61, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077 \[ \frac{a^3 x^{m+1}}{m+1}+\frac{3 a^2 b x^{m+4}}{m+4}+\frac{3 a b^2 x^{m+7}}{m+7}+\frac{b^3 x^{m+10}}{m+10} \]
Antiderivative was successfully verified.
[In] Int[x^m*(a + b*x^3)^3,x]
[Out]
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Rubi in Sympy [A] time = 9.97688, size = 53, normalized size = 0.87 \[ \frac{a^{3} x^{m + 1}}{m + 1} + \frac{3 a^{2} b x^{m + 4}}{m + 4} + \frac{3 a b^{2} x^{m + 7}}{m + 7} + \frac{b^{3} x^{m + 10}}{m + 10} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**m*(b*x**3+a)**3,x)
[Out]
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Mathematica [A] time = 0.0417095, size = 55, normalized size = 0.9 \[ x^m \left (\frac{a^3 x}{m+1}+\frac{3 a^2 b x^4}{m+4}+\frac{3 a b^2 x^7}{m+7}+\frac{b^3 x^{10}}{m+10}\right ) \]
Antiderivative was successfully verified.
[In] Integrate[x^m*(a + b*x^3)^3,x]
[Out]
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Maple [B] time = 0.007, size = 178, normalized size = 2.9 \[{\frac{{x}^{1+m} \left ({b}^{3}{m}^{3}{x}^{9}+12\,{b}^{3}{m}^{2}{x}^{9}+39\,{b}^{3}m{x}^{9}+3\,a{b}^{2}{m}^{3}{x}^{6}+28\,{b}^{3}{x}^{9}+45\,a{b}^{2}{m}^{2}{x}^{6}+162\,a{b}^{2}m{x}^{6}+3\,{a}^{2}b{m}^{3}{x}^{3}+120\,a{b}^{2}{x}^{6}+54\,{a}^{2}b{m}^{2}{x}^{3}+261\,{a}^{2}bm{x}^{3}+{a}^{3}{m}^{3}+210\,{a}^{2}b{x}^{3}+21\,{a}^{3}{m}^{2}+138\,{a}^{3}m+280\,{a}^{3} \right ) }{ \left ( 10+m \right ) \left ( 7+m \right ) \left ( 4+m \right ) \left ( 1+m \right ) }} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^m*(b*x^3+a)^3,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^3 + a)^3*x^m,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.246054, size = 212, normalized size = 3.48 \[ \frac{{\left ({\left (b^{3} m^{3} + 12 \, b^{3} m^{2} + 39 \, b^{3} m + 28 \, b^{3}\right )} x^{10} + 3 \,{\left (a b^{2} m^{3} + 15 \, a b^{2} m^{2} + 54 \, a b^{2} m + 40 \, a b^{2}\right )} x^{7} + 3 \,{\left (a^{2} b m^{3} + 18 \, a^{2} b m^{2} + 87 \, a^{2} b m + 70 \, a^{2} b\right )} x^{4} +{\left (a^{3} m^{3} + 21 \, a^{3} m^{2} + 138 \, a^{3} m + 280 \, a^{3}\right )} x\right )} x^{m}}{m^{4} + 22 \, m^{3} + 159 \, m^{2} + 418 \, m + 280} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^3 + a)^3*x^m,x, algorithm="fricas")
[Out]
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Sympy [A] time = 9.83612, size = 666, normalized size = 10.92 \[ \begin{cases} - \frac{a^{3}}{9 x^{9}} - \frac{a^{2} b}{2 x^{6}} - \frac{a b^{2}}{x^{3}} + b^{3} \log{\left (x \right )} & \text{for}\: m = -10 \\- \frac{a^{3}}{6 x^{6}} - \frac{a^{2} b}{x^{3}} + 3 a b^{2} \log{\left (x \right )} + \frac{b^{3} x^{3}}{3} & \text{for}\: m = -7 \\- \frac{a^{3}}{3 x^{3}} + 3 a^{2} b \log{\left (x \right )} + a b^{2} x^{3} + \frac{b^{3} x^{6}}{6} & \text{for}\: m = -4 \\a^{3} \log{\left (x \right )} + a^{2} b x^{3} + \frac{a b^{2} x^{6}}{2} + \frac{b^{3} x^{9}}{9} & \text{for}\: m = -1 \\\frac{a^{3} m^{3} x x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{21 a^{3} m^{2} x x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{138 a^{3} m x x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{280 a^{3} x x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{3 a^{2} b m^{3} x^{4} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{54 a^{2} b m^{2} x^{4} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{261 a^{2} b m x^{4} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{210 a^{2} b x^{4} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{3 a b^{2} m^{3} x^{7} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{45 a b^{2} m^{2} x^{7} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{162 a b^{2} m x^{7} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{120 a b^{2} x^{7} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{b^{3} m^{3} x^{10} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{12 b^{3} m^{2} x^{10} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{39 b^{3} m x^{10} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} + \frac{28 b^{3} x^{10} x^{m}}{m^{4} + 22 m^{3} + 159 m^{2} + 418 m + 280} & \text{otherwise} \end{cases} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**m*(b*x**3+a)**3,x)
[Out]
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GIAC/XCAS [A] time = 0.236883, size = 346, normalized size = 5.67 \[ \frac{b^{3} m^{3} x^{10} e^{\left (m{\rm ln}\left (x\right )\right )} + 12 \, b^{3} m^{2} x^{10} e^{\left (m{\rm ln}\left (x\right )\right )} + 39 \, b^{3} m x^{10} e^{\left (m{\rm ln}\left (x\right )\right )} + 3 \, a b^{2} m^{3} x^{7} e^{\left (m{\rm ln}\left (x\right )\right )} + 28 \, b^{3} x^{10} e^{\left (m{\rm ln}\left (x\right )\right )} + 45 \, a b^{2} m^{2} x^{7} e^{\left (m{\rm ln}\left (x\right )\right )} + 162 \, a b^{2} m x^{7} e^{\left (m{\rm ln}\left (x\right )\right )} + 3 \, a^{2} b m^{3} x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + 120 \, a b^{2} x^{7} e^{\left (m{\rm ln}\left (x\right )\right )} + 54 \, a^{2} b m^{2} x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + 261 \, a^{2} b m x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + a^{3} m^{3} x e^{\left (m{\rm ln}\left (x\right )\right )} + 210 \, a^{2} b x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + 21 \, a^{3} m^{2} x e^{\left (m{\rm ln}\left (x\right )\right )} + 138 \, a^{3} m x e^{\left (m{\rm ln}\left (x\right )\right )} + 280 \, a^{3} x e^{\left (m{\rm ln}\left (x\right )\right )}}{m^{4} + 22 \, m^{3} + 159 \, m^{2} + 418 \, m + 280} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^3 + a)^3*x^m,x, algorithm="giac")
[Out]